Sertakan caranya ya.... 1). Hasil perkalian dari √6(2√3-√32) adalah.... 2). Hasil perkalian (√6+√3)(2√3-√6) adalah.... 3). Hasil dari (√5+√3)² = .... 4). Hasil

Semoga membantu yaa:)

[tex]$\begin{align} 1.)~~~~\sqrt{6}(2 \sqrt{3} - \sqrt{32} ) &= 2\sqrt{18} - \sqrt{192} \\&= 2\sqrt{2 \ . \ 9} - \sqrt{3 \ . \ 64} \\&= 6 \sqrt{2} - 8\sqrt{3} \end{align}[/tex]

[tex]$\begin{align}2.)~~~~( \sqrt{6} + \sqrt{3} )( 2\sqrt{3} - \sqrt{6} ) &= 2 \sqrt{18} - \sqrt{36} + 2 \sqrt{9} - \sqrt{18} \\&= 6 \sqrt{2} - 6 +6 \sqrt{2} - 3 \sqrt{2} \\ &= 9 \sqrt{2} - 6 \end{align}[/tex]

[tex]$\begin{align}3.)~~~~( \sqrt{5} + \sqrt{3} )^2 &= ( \sqrt{5} )^2 + 2( \sqrt{5} )( \sqrt{3}) + (\sqrt{3} )^2 \\ &= 5 + 2 \sqrt{15} + 3 \\ &= 8 + 2\sqrt{15} \end{align}[/tex]

[tex]$\begin{align}4.)~~~~(4a \sqrt{3} - 3)^2 &= (4a \sqrt{3} )^2 - 2(4a \sqrt{3} )(3) + 3^2 \\&= 48a^2 - 24a \sqrt{3} + 9\end{align}[/tex]

[tex]$\begin{align}6.)~~~~ \frac{5}{5 + \sqrt{3} } &= \frac{5}{5 + \sqrt{3} } \ . \ \frac{5 - \sqrt{3} }{5 - \sqrt{3} } \\ &= \frac{25 - 5 \sqrt{3} }{25 - 3} \\&= \frac{25 - 5 \sqrt{3} }{22} \end{align}[/tex]

[tex]$\begin{align} 7.)~~~~ \frac{3}{ \sqrt{a} - 2 \sqrt{b} } &= \frac{3}{ \sqrt{a} - 2 \sqrt{b} } \ . \ \frac{ \sqrt{a} + 2 \sqrt{b} }{ \sqrt{a} + 2\sqrt{b} } \\&= \frac{3 \sqrt{a} + 6 \sqrt{ab} }{a - 4b} \end{align}[/tex]

[tex]$\begin{align}8.)~~~~ \sqrt{14} + 2 \sqrt{24} &= \sqrt{14} + 4 \sqrt{6} \end{align}[/tex]

Untuk nomer 5 soal nya kurang lengkap