Matematika

Pertanyaan

tolong yaa kak.....................
tolong yaa kak.....................

1 Jawaban

  • PQ = PR
    ∠QPR = 50°
    ∠PQR = ∠QRP = (180 - 50) / 2 = 130 / 2 = 65°

    ∠UQR = ∠QRU = 1/2 x 65 = 32,5°

    ∠QUR = 180 - ∠UQR - ∠QRU
                = 180 - 32,5 - 32,5
                = 115°

    jawaban D