Bantu ya no 69 please

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Diket :
suhu awal, T1 = 30°C
suhu akhir, T2 = 10°C
Beda suhu, ΔT = T2 - T1 = 10°C - 30°C = - 20°C 
hambatan awal, R1 = 420 ohm
koef muai suhu kawat, α = 0,0025 /°C

Tanya :
Hambatan akhir, R2 = __?

Jawab : 

R2 = R1.(1 + α.ΔT)
R2 = 420.(1 + 0,0025.(- 20))
R2 = 420.(1 - 0,05)
R2 = 420.(0,95)
R2 = 399 ohm

Jawaban : D

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FZA