Integral - Pengertian Integral Tentu Fungsi Aljabar

InTegraL Tentu

∫dx /x² = 1/2 [2a...-1]
∫x^-2 dx = 1/2
-1/x [2a...-1] = 1/2
-1/(2a) - (-1/-1) = 1/2
-1/(2a) - 1 = 1/2
-1/(2a) = 1 + 1/2
-1/(2a) = 3/2
-1/a = 3
a = -1/3