Kedalam 900 gram air dilarutkan 3,6 gram urea (mr=60). Jika pada suhu 20•c tekanan uap air 17,59 mmhg. Maka tentukan penurunan tekanan uap larutan dan tekanan

dik: gH2O = 900gr
mr H2O = 18
g urea = 3,6gr
mr urea = 60
Po = 17,59mmhg
T = 20C -> 293K
dit: delta P dan P
jwb:
delta P = Po × Xt
delta P = 17,59 mmhg × [3,6/60 / 3,6/60+900/18]
delta P = 17,59 × 0,001
delta P = 0,01759

P = Po - delta P
P = 17,59 - 0,01759
P = 17,57241