jika p(n) = 3n + 8 / n-1, tentukan: p(n+1)-p(n).

p(n) =[tex] \frac{3n+8}{n-1} [/tex]
p(n+1)-p(n)= [tex] \frac{3(n+1)+8}{(n+1)-1} - \frac{3n+8}{n-1} [/tex]
=[tex] \frac{3n+11}{n} - \frac{3n+8}{n-1} [/tex]
=[tex] \frac{6n^{2}+22n+11}{n^{2}+n} [/tex]