Integral π/0 sin(2x-π)dx

InTegraL

∫sin (2x - π) dx [π...0]
= -1/2 ∫2 sin (2x - π) dx
= -1/2 ∫dcos (2x - π)
= -1/2 cos (2x - π)
= -1/2 (cos (2π - π) - cos (0 - π))
= -1/2 (-1 - (-1))
= 0

integral Trigonometri

[tex] \int\limits^ \pi_0 {sin (2x - \pi) } \, dx \ = \\ .\\ = \ - \frac{1}{2} [cos (2x \ - \ \pi )] \ (pi \ . . \ 0) \\ . \\ = - \frac{1}{2} \ (cos \pi - \ cos \ ( \ -pi )) \\ \\ = - \frac{1}{2}\ (-1 - (-1)) \ = - \frac{1}{2}\ (0)\ = \ 0 [/tex]