Larutan glukosa (Mr=180) dalam 100 gram air (Kb=0,52) dicampurkan dengan 34 gram CaSO4 (Mr=136) dalam 100 gram air dan mendidih pada suhu 101,82 C. Berat glukos

zat A :
Mr = 180
wp = 100 gram
Zat B :
wt = 34 gram
Mr = 136
wp = 100 gram
Kb = 0,52°C
Tb = 101,82

mB = 34/136 x 1000/100 = 2,5 molal

ΔTb = (mA + mB) Kb
1,82 = (mA + 2,5) 0.52
1,82 = 0,52.mA + 1,3
0,52.mA = 1,82 - 1,3
mA = 0,52/0,52
mA = 1 molal

mA = wt/Mr x 1000/wp
1 = wt/180 x 1000/100
1 = wt/18
wt = 18 gram