Diketahui (a, b) memenuhi sistem persamaan eksponensial : [tex] \left \{ {{2^x^+^1 - 3^y =7} \atop {-2^x^-^1-3^y^+^1=-5}} \right. [/tex] Nilai dari ekspresi (a+

Bab Eksponensial
Matematika SMA Kelas X

^ = pangkat

2^x = p
3^y = q

2^(x + 1) - 3^y= 7
2^x . 2 - 3^y = 7
2p - q = 7

-2^(x - 1) - 3^(y + 1) = -5
-2^x . 2⁻¹ - 3^y . 3 = -5
-p/2 - 3q = -5

**dikalikan -4**

2p + 12q = 20
2p  -     q =   7
--------------------- -
        13q = 13
            q = 1

2p - q = 7
2p - 1 = 7
2p = 7 + 1
p = 8/2
p = 4

2^x = p
2^x = 4
2^x = 2^2
x = 2

3^y = 1
3^y = 3^0
y = 0

hasil penjumlahannya = 2 + 0
                                    = 2