Matematika

Pertanyaan

3 akar 8^x+2=(1/32)^2-x adalah

1 Jawaban

  • 3)
    V(8^(x+2)) = (1/32)^(2-x)
    ((2^3)^(x+2))^1/2 = (1/2^5)^(2-x)
    (2^(3x+6))^1/2 = (2^(-5))^(2-x)
    (2^(3x/2 + 3)) = 2^(-10+5x)
    3x/2 + 3 = -10 + 5x
    3x/2 - 5x = -10 - 3
    3x/2 - 10x/2 = -13
    -7x/2 = -13
    -7x = -13 × 2
    -7x = -26
    x = -26/-7
    x = 26/7

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