larutan CH3COOH 0,4 M Ka = 1×10-5
Kimia
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Pertanyaan
larutan CH3COOH 0,4 M Ka = 1×10-5
1 Jawaban
-
1. Jawaban ionkovalen
H+ = akar Ka Ma
= akar 10-5 x 4.10-1
= akar 4.10-6
= 2.10-3 M
pH = - log 2.10-3
= 3 - log 2