Matematika

Pertanyaan

Darurat!!! Tolonggg dibantu pakai caraa
Darurat!!! Tolonggg dibantu pakai caraa

1 Jawaban

  • [tex] \sqrt[5]{2x^{3}.x^{1/2}} . x^{1/2}\sqrt{3} \\ \sqrt[5]{2x^{7/2}} . x^{1/2}\sqrt{3} \\ \sqrt[5]{2}.x^{7/10} . x^{1/2}\sqrt{3} \\ x^{7/20}\sqrt[5]{2}\sqrt{3}[/tex]