selesaikan operasi akar berikut !! a) 2√2 + 4√8 - 2√27 b) 3 √12 - 5 √ 48 + 2√75 c) √2 × √12 d) √6 ×√ 18
Matematika
fadillahazzahra141
Pertanyaan
selesaikan operasi akar berikut !!
a) 2√2 + 4√8 - 2√27
b) 3 √12 - 5 √ 48 + 2√75
c) √2 × √12
d) √6 ×√ 18
a) 2√2 + 4√8 - 2√27
b) 3 √12 - 5 √ 48 + 2√75
c) √2 × √12
d) √6 ×√ 18
2 Jawaban
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1. Jawaban onnyfathi
a. 2√2+4√8-2√27
= 2√2+8√2-6√3
= 10√2-6√3
b. 3√12-5√48+2√75
= 6√3-20√3+10√3
= -4√3
c. √2×√12
= √24
= 2√6
d. √6×√18
= √108
= 6√3 -
2. Jawaban Faizafrian
a. 2√2 + 4√8 - 2√27 = 2√2 + 4√(4x2) - 2√(9x3) = 2√2 + (4 x √4 x √2) - (2 x √9 x √3) = 2√2 + 8√2 - 9√3 = 10√2 - 9√3
b. 3√12 - 5√48 + 2√75 = (3 x √4 x √3) - (5 x √16 x √3) + (2 x √25 x √3) = 6√3 - 20√3 + 10√3 = -4√3
c. √2 x √12 = √(2 x 12) = √24 = √4 x √6 = 2√6
d. √6 x √18 = √(6 x 18) = √108 = √36 x √3 = 6√3