cara nya gimana tolong kerjain yaaa...mengunakan metode eliminasi ,subtitusi

x + y + z = 6 (i)
2x - y + 3z = 7 (ii)
3x + y - 2z = 9 (iii)

eliminasi pers (i) Dan (ii)
x + y + z = 6
2x - y + 3z = 7
---------------------- +
3x + 4z = 13 (iv)

eliminasi pers (ii) Dan (iii)
2x - y + 3z = 7
3x + y - 2z = 9
--------------------- +
5x + z = 16 (v)

eliminasi pers (iv) Dan (v)
3x + 4z = 13 dikali 1
5x + z = 16 dikali 4

3x + 4z = 13
20x + 4z = 64
--------------------- -
-17x = -51
x = -51/-17
x = 3

substitusikan pers (iv) dgn x = 3
3x + 4z = 13
3(3) + 4z = 13
9 + 4z = 13
4z = 13 - 9
4z = 4
z = 4/4
z = 1

substitusikan pers (i) dgn x = 3 dan z = 1
x + y + z = 6
3 + y + 1 = 6
y + 4 = 6
y = 6 - 4
y = 2

jadi
x = 3
y = 2
z = 1