2log 16 - 3log27-5log625

Materi : Logaritma
Kelas : X SMA

^2 = Basis 2
^3 = basis 3
^5 = basis 5

^2 log16 - ^3 log27 - ^5 log625
= 2^4 - 3^3 - 5^4
= 4 - 3 - 4
= -3

Jawaban sudah tepat

[tex]^2\log16-^3\log27-^5\log625\\ =^2\log2^4-^3\log3^3-^5\log5^4\\ =4-3-4\\ =1-4\\ \bold{=-3}[/tex]