tolong dibantu ya, hitunglah ph larutan (CH3COOH) 0,00025 M (ka = 1x10¯5) ➡ ps; 10¯5 sepuluh pangkat lima

Diket : Ka : 1× 10^-5
a : 2,5 × 10^-4
ditanya : pH?
jawab :
[H+] =√Ka × a
=√(1 × 10^-5 )(2,5 × 10^-4)
=√2,5 × 10^-9 = 2,5 × 10^-3

Ph = - log [H+]
= - log 2,5 × 10^-3
= 3 - log 2,5
= 3- 0,39
= 2,61

Jadi,Ph larutan 2,61