Matematika

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Bentuk sederhana dr 8 log 32 + 8 log 16 + 8 log 128

1 Jawaban

  • 8 log 32 + 8 log 16 + 8 log 128
    = (2³) log (2^5) + (2³) log (2^4) + (2³) log (2^7)
    = (5/3) ²log2 + (4/3) ²log2 + (7/3) ²log2
    = (5/3) + (4/3) + (7/3)
    = 16/3

    semoga bisa membantu :)

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