Nilai mutlak [6x+12]+[x-4]<8

|6x+12| + |x-4| < 8
6x + 12 + x - 4 < 8
6x + x + 12 - 4 < 8
7x + 8 < 8
7x < 8 - 8
7x < 0
x < 0/7

|6x+12| + |x-4| > -8
6x + 12 + x - 4 > -8
6x + x + 12 - 4 > -8
7x + 8 > -8
7x > - 8 - 8
7x > -16
x > -16/7
x > -2 2/7

J A D I K A N J A W A B A N T E R B A I K
*maaf bila salah